Validating xml in java Free sex booty came
The following details the code how to use them with SAX.SAXParser Factory factory = SAXParser Instance(); Namespace Aware(true); Validating(true); XMLReader reader = SAXParser()XMLReader(); // Set XSD as the schema language Property(" Language", " // Use XML catalogs Entity Resolver(new Catalog Resolver()); Input Stream stream = get Class()Class Loader()Resource As Stream("person.xml"); reader.parse(new Input Source(stream)); Beware: the Catalog Resolver class is available in the JDK in an internal package, but the Apache XML resolver library does the job.
* * @param node The document (or child node) to traverse seeking processing * instruction nodes.Visit Stack Exchange As this related question describes, there does not appear to be a canonical way to validate XML files against an XSD then subsequently transform them using an XSL template with file paths determined from a catalog resolver. The XSL templates can be XSLT 1.0 or XSLT 2.0, the latter requiring Saxon9HE. However, this isn’t always the best strategy to choose from.For example, Spring provides its different schemas inside JARs, along classes and validation is done against those schemas.